1)[(–1+3)·(–2)]3:(–5–3)=
2)[(–2)2]2–[3·(–5+4)]3=
3)[(–2+3)·(–3)]2:(–6+3)=
4)[(–2)3:(–2)]–[4·(–8+7)]3=
5)[(–6+7–15):(–7)]3–[–3·(–3)]=
6)[49:( 24–35+4)]2+[–36–(–10–21)]3=
7){[–16:(–8)]–(–6+4)}2:[(–1)·(–3)0]3=
8) [(–1)3·
(–2)3· (–3)3]=
9)[–16+35+48+(–1)9]–(–16+27–35)0=
10)[(–2)3·(–4+5)6]–[(–20)0·(–2)]2=
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